Greetings, SQL enthusiasts and eager learners! Today, we delve into the world of SQL assignments, unraveling complex queries, and providing insightful solutions. At programminghomeworkhelp.com, our mission is to empower students with the knowledge and skills necessary to conquer SQL challenges confidently. Whether you're a novice or an experienced coder, our SQL assignment help service is here to guide you through the intricacies of database management.
Question 1: Analyzing Sales Data
Consider a scenario where you're tasked with analyzing sales data from a retail database. You need to retrieve the top 5 best-selling products along with their sales revenue for the current year. Additionally, you must display the percentage of total sales revenue each product contributes.
Solution:
SELECT
product_id,
product_name,
SUM(quantity * unit_price) AS total_sales,
SUM(quantity * unit_price) / (SELECT SUM(quantity * unit_price) FROM sales WHERE YEAR(sale_date) = YEAR(CURRENT_DATE())) * 100 AS percentage_of_total
FROM
products
JOIN
sales ON products.id = sales.product_id
WHERE
YEAR(sale_date) = YEAR(CURRENT_DATE())
GROUP BY
product_id, product_name
ORDER BY
total_sales DESC
LIMIT 5;
In this solution:
- We use a JOIN operation to combine the
products
andsales
tables based on the commonproduct_id
. - The
SUM()
function calculates the total sales revenue for each product. - We utilize a subquery to calculate the total sales revenue for the current year.
- Finally, we present the top 5 best-selling products along with their respective sales revenue and percentage of total sales.
Question 2: Employee Hierarchy Analysis
Imagine you're working with an employee database that stores hierarchical data using the adjacency list model. Your task is to retrieve the names of all employees along with their respective manager's name.
Solution:
WITH RECURSIVE EmployeeHierarchy AS (
SELECT
id,
name,
manager_id
FROM
employees
WHERE
manager_id IS NULL -- Assuming top-level managers have NULL manager_id
UNION ALL
SELECT
e.id,
e.name,
e.manager_id
FROM
employees e
INNER JOIN
EmployeeHierarchy eh ON e.manager_id = eh.id
)
SELECT
e.name AS employee_name,
m.name AS manager_name
FROM
EmployeeHierarchy e
LEFT JOIN
employees m ON e.manager_id = m.id;
In this solution:
- We utilize a Common Table Expression (CTE) with the
RECURSIVE
keyword to traverse the employee hierarchy recursively. - The initial query selects top-level managers.
- The recursive part joins employees with their respective managers.
- Finally, we retrieve the names of all employees along with their manager's name using a LEFT JOIN operation.
With these expertly crafted solutions, you can approach SQL assignments with confidence and finesse. Remember, mastering SQL is not just about writing queries; it's about understanding data relationships and leveraging the power of SQL to extract meaningful insights.
At programminghomeworkhelp.com, we're dedicated to your success. Whether you need assistance with SQL assignments or want to deepen your understanding of database management, our team of experts is here to support you every step of the way.